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0=3x^2-17x-8
We move all terms to the left:
0-(3x^2-17x-8)=0
We add all the numbers together, and all the variables
-(3x^2-17x-8)=0
We get rid of parentheses
-3x^2+17x+8=0
a = -3; b = 17; c = +8;
Δ = b2-4ac
Δ = 172-4·(-3)·8
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{385}}{2*-3}=\frac{-17-\sqrt{385}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{385}}{2*-3}=\frac{-17+\sqrt{385}}{-6} $
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